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X^2+9X-112X=0
We add all the numbers together, and all the variables
X^2-103X=0
a = 1; b = -103; c = 0;
Δ = b2-4ac
Δ = -1032-4·1·0
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10609}=103$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-103}{2*1}=\frac{0}{2} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+103}{2*1}=\frac{206}{2} =103 $
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